3.4.73 \(\int x \sqrt [3]{a+b x} \, dx\)

Optimal. Leaf size=34 \[ \frac {3 (a+b x)^{7/3}}{7 b^2}-\frac {3 a (a+b x)^{4/3}}{4 b^2} \]

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Rubi [A]  time = 0.01, antiderivative size = 34, normalized size of antiderivative = 1.00, number of steps used = 2, number of rules used = 1, integrand size = 11, \(\frac {\text {number of rules}}{\text {integrand size}}\) = 0.091, Rules used = {43} \begin {gather*} \frac {3 (a+b x)^{7/3}}{7 b^2}-\frac {3 a (a+b x)^{4/3}}{4 b^2} \end {gather*}

Antiderivative was successfully verified.

[In]

Int[x*(a + b*x)^(1/3),x]

[Out]

(-3*a*(a + b*x)^(4/3))/(4*b^2) + (3*(a + b*x)^(7/3))/(7*b^2)

Rule 43

Int[((a_.) + (b_.)*(x_))^(m_.)*((c_.) + (d_.)*(x_))^(n_.), x_Symbol] :> Int[ExpandIntegrand[(a + b*x)^m*(c + d
*x)^n, x], x] /; FreeQ[{a, b, c, d, n}, x] && NeQ[b*c - a*d, 0] && IGtQ[m, 0] && ( !IntegerQ[n] || (EqQ[c, 0]
&& LeQ[7*m + 4*n + 4, 0]) || LtQ[9*m + 5*(n + 1), 0] || GtQ[m + n + 2, 0])

Rubi steps

\begin {align*} \int x \sqrt [3]{a+b x} \, dx &=\int \left (-\frac {a \sqrt [3]{a+b x}}{b}+\frac {(a+b x)^{4/3}}{b}\right ) \, dx\\ &=-\frac {3 a (a+b x)^{4/3}}{4 b^2}+\frac {3 (a+b x)^{7/3}}{7 b^2}\\ \end {align*}

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Mathematica [A]  time = 0.01, size = 24, normalized size = 0.71 \begin {gather*} \frac {3 (a+b x)^{4/3} (4 b x-3 a)}{28 b^2} \end {gather*}

Antiderivative was successfully verified.

[In]

Integrate[x*(a + b*x)^(1/3),x]

[Out]

(3*(a + b*x)^(4/3)*(-3*a + 4*b*x))/(28*b^2)

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IntegrateAlgebraic [A]  time = 0.01, size = 35, normalized size = 1.03 \begin {gather*} -\frac {3 \sqrt [3]{a+b x} \left (3 a^2-a b x-4 b^2 x^2\right )}{28 b^2} \end {gather*}

Antiderivative was successfully verified.

[In]

IntegrateAlgebraic[x*(a + b*x)^(1/3),x]

[Out]

(-3*(a + b*x)^(1/3)*(3*a^2 - a*b*x - 4*b^2*x^2))/(28*b^2)

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fricas [A]  time = 0.91, size = 30, normalized size = 0.88 \begin {gather*} \frac {3 \, {\left (4 \, b^{2} x^{2} + a b x - 3 \, a^{2}\right )} {\left (b x + a\right )}^{\frac {1}{3}}}{28 \, b^{2}} \end {gather*}

Verification of antiderivative is not currently implemented for this CAS.

[In]

integrate(x*(b*x+a)^(1/3),x, algorithm="fricas")

[Out]

3/28*(4*b^2*x^2 + a*b*x - 3*a^2)*(b*x + a)^(1/3)/b^2

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giac [B]  time = 1.04, size = 67, normalized size = 1.97 \begin {gather*} \frac {3 \, {\left (\frac {7 \, {\left ({\left (b x + a\right )}^{\frac {4}{3}} - 4 \, {\left (b x + a\right )}^{\frac {1}{3}} a\right )} a}{b} + \frac {2 \, {\left (2 \, {\left (b x + a\right )}^{\frac {7}{3}} - 7 \, {\left (b x + a\right )}^{\frac {4}{3}} a + 14 \, {\left (b x + a\right )}^{\frac {1}{3}} a^{2}\right )}}{b}\right )}}{28 \, b} \end {gather*}

Verification of antiderivative is not currently implemented for this CAS.

[In]

integrate(x*(b*x+a)^(1/3),x, algorithm="giac")

[Out]

3/28*(7*((b*x + a)^(4/3) - 4*(b*x + a)^(1/3)*a)*a/b + 2*(2*(b*x + a)^(7/3) - 7*(b*x + a)^(4/3)*a + 14*(b*x + a
)^(1/3)*a^2)/b)/b

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maple [A]  time = 0.00, size = 21, normalized size = 0.62 \begin {gather*} -\frac {3 \left (b x +a \right )^{\frac {4}{3}} \left (-4 b x +3 a \right )}{28 b^{2}} \end {gather*}

Verification of antiderivative is not currently implemented for this CAS.

[In]

int(x*(b*x+a)^(1/3),x)

[Out]

-3/28*(b*x+a)^(4/3)*(-4*b*x+3*a)/b^2

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maxima [A]  time = 1.29, size = 26, normalized size = 0.76 \begin {gather*} \frac {3 \, {\left (b x + a\right )}^{\frac {7}{3}}}{7 \, b^{2}} - \frac {3 \, {\left (b x + a\right )}^{\frac {4}{3}} a}{4 \, b^{2}} \end {gather*}

Verification of antiderivative is not currently implemented for this CAS.

[In]

integrate(x*(b*x+a)^(1/3),x, algorithm="maxima")

[Out]

3/7*(b*x + a)^(7/3)/b^2 - 3/4*(b*x + a)^(4/3)*a/b^2

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mupad [B]  time = 0.03, size = 25, normalized size = 0.74 \begin {gather*} -\frac {21\,a\,{\left (a+b\,x\right )}^{4/3}-12\,{\left (a+b\,x\right )}^{7/3}}{28\,b^2} \end {gather*}

Verification of antiderivative is not currently implemented for this CAS.

[In]

int(x*(a + b*x)^(1/3),x)

[Out]

-(21*a*(a + b*x)^(4/3) - 12*(a + b*x)^(7/3))/(28*b^2)

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sympy [B]  time = 1.20, size = 202, normalized size = 5.94 \begin {gather*} - \frac {9 a^{\frac {13}{3}} \sqrt [3]{1 + \frac {b x}{a}}}{28 a^{2} b^{2} + 28 a b^{3} x} + \frac {9 a^{\frac {13}{3}}}{28 a^{2} b^{2} + 28 a b^{3} x} - \frac {6 a^{\frac {10}{3}} b x \sqrt [3]{1 + \frac {b x}{a}}}{28 a^{2} b^{2} + 28 a b^{3} x} + \frac {9 a^{\frac {10}{3}} b x}{28 a^{2} b^{2} + 28 a b^{3} x} + \frac {15 a^{\frac {7}{3}} b^{2} x^{2} \sqrt [3]{1 + \frac {b x}{a}}}{28 a^{2} b^{2} + 28 a b^{3} x} + \frac {12 a^{\frac {4}{3}} b^{3} x^{3} \sqrt [3]{1 + \frac {b x}{a}}}{28 a^{2} b^{2} + 28 a b^{3} x} \end {gather*}

Verification of antiderivative is not currently implemented for this CAS.

[In]

integrate(x*(b*x+a)**(1/3),x)

[Out]

-9*a**(13/3)*(1 + b*x/a)**(1/3)/(28*a**2*b**2 + 28*a*b**3*x) + 9*a**(13/3)/(28*a**2*b**2 + 28*a*b**3*x) - 6*a*
*(10/3)*b*x*(1 + b*x/a)**(1/3)/(28*a**2*b**2 + 28*a*b**3*x) + 9*a**(10/3)*b*x/(28*a**2*b**2 + 28*a*b**3*x) + 1
5*a**(7/3)*b**2*x**2*(1 + b*x/a)**(1/3)/(28*a**2*b**2 + 28*a*b**3*x) + 12*a**(4/3)*b**3*x**3*(1 + b*x/a)**(1/3
)/(28*a**2*b**2 + 28*a*b**3*x)

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